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Q.
In the uranium radioactive series, the initial nucleus is $_{92}U^{238}$ and that the final nucleus is $_{82}Pb^{206}$. When uranium nucleus decays to lead, the number of a particles and b particles emitted are
Let no. of $\alpha$ particles emitted be $x$ and no. of $\beta$ particles emitted be $y$.
Difference in mass no.$ 4 x = 238 - 206 = 32$
$x = 8$
Difference in charge no. $2x - 1y = 92 - 82 = 10$
$16 - y = 10$ or $y = 6$