Question

In the shown common emitter amplifier circuit, $\beta =80,V_{BE}=0.7V$. The value of $R_C$ (in $k\Omega$ ) is

Answer 1

Answer: 2.50

$V_{BE}=0.7V=8.7-I_B\left(200\times 10^3\right)$
$\Rightarrow I_B=\frac{8}{200\times 10^3}=4\times 10^{-5}A$
$\Rightarrow \beta =80=\frac{I_C}{I_B}$
$\Rightarrow I_C=32\times 10^{-4}A$
$V_{CE}=3V=11-I_C{R}_C$
$3=11-32\times 10^{-4}{R}_C$
$\Rightarrow R_C=\frac{8}{32\times 10^{-4}}$
$R_C=2.5k\Omega$