In the setup shown, a 200 N block is supported in equilibrium with the help of strings and a spring. At point O, the strings are knotted. If the extension in the spring is 4 cm, then the force constant (in N / m ) of the spring is closest to (g=10 m / s 2)

Question

In the setup shown, a 200 N block is supported in equilibrium with the help of strings and a spring. At point O, the strings are knotted. If the extension in the spring is 4 cm, then the force constant (in N / m ) of the spring is closest to (g=10 m / s 2) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Sigma Fx=0 ⇒ T2=160 N Sigma Fy=0 ⇒ T1=120 N Spring constant, k=(120 N /4 cm )=3000 N / m

Q. In the setup shown, a $200 N$ block is supported in equilibrium with the help of strings and a spring. At point $O$ , the strings are knotted. If the extension in the spring is $4 c m$ , then the force constant (in $N / m$ ) of the spring is closest to $(g = 10 m / s^{2})$

$Σ F_{x} = 0$
$\Rightarrow T_{2} = 160 N$
$Σ F_{y} = 0$
$\Rightarrow T_{1} = 120 N$
Spring constant,
$k = \frac{120 N}{4 c m} = 3000 N / m$

Q. In the setup shown, a 200N block is supported in equilibrium with the help of strings and a spring. At point O, the strings are knotted. If the extension in the spring is 4cm, then the force constant (in N/m ) of the spring is closest to (g=10m/s2)

ΣFx​=0 ⇒T2​=160N ΣFy​=0 ⇒T1​=120N Spring constant, k=4cm120N​=3000N/m

Q. In the setup shown, a $200 N$ block is supported in equilibrium with the help of strings and a spring. At point $O$ , the strings are knotted. If the extension in the spring is $4 c m$ , then the force constant (in $N / m$ ) of the spring is closest to $(g = 10 m / s^{2})$

$Σ F_{x} = 0$
$\Rightarrow T_{2} = 160 N$
$Σ F_{y} = 0$
$\Rightarrow T_{1} = 120 N$
Spring constant,
$k = \frac{120 N}{4 c m} = 3000 N / m$