Q.
In the setup shown, a $200 \,N$ block is supported in equilibrium with the help of strings and a spring. At point $O$, the strings are knotted. If the extension in the spring is $4 \,cm$, then the force constant (in $N / m$ ) of the spring is closest to $\left(g=10 \,m / s ^{2}\right)$
Laws of Motion
Solution:
$\Sigma F_{x}=0$
$ \Rightarrow T_{2}=160\, N$
$\Sigma F_{y}=0$
$ \Rightarrow T_{1}=120\, N$
Spring constant,
$k=\frac{120 \,N }{4\, cm }=3000\, N / m$
