In the Rosenmund's reaction, RCOCl + H2 xrightarrowPd/BaSO4 RCHO + HCl Here BaSO4

Question

In the Rosenmund's reaction, RCOCl + H2 xrightarrowPd/BaSO4 RCHO + HCl Here BaSO4 (A) promotes catalytic activity of Pd (B) removes the HCl formed in the reaction (C) deactivates palladium (D) activates palladium

Tardigrade Admin · Accepted Answer

In the Rosenmund's reaction, acid chlorides are converted to corresponding aldehydes by catalytic reduction.
The reaction is carried out by passing through a hot solution of the acid chloride in the presence of

P d

deposited over

B a S O_{4}

.
Here, barium sulphate decrease the activity of palladium.

RCOCl + H_{2} P d / B a S O_{4} RC H O + H Cl

Q. In the Rosenmund's reaction, RCOCl+H2​Pd/BaSO4​​RCHO+HCl Here BaSO4​

promotes catalytic activity of Pd

removes the HCl formed in the reaction

deactivates palladium

activates palladium

Q. In the Rosenmund's reaction,
$RCOCl + H_{2} P d / B a S O_{4} RC H O + H Cl$
Here $B a S O_{4}$