Question

In the relation : $\frac{dy}{dt}=2\omega \sin \left(\omega t+{\varphi }_0\right),$ the dimensional formula for $\left(\omega t+{\varphi }_0\right)$ is:

• A. $[MLT]$
• B. $[ML{T}^0]$
• C. $\left[M{L}^0{T}^0\right]$
• D. $[M^0{L}^0{T}^0]$

Answer 1

Answer: (D)

Here, $\left(\omega t+{\varphi }_0\right)$ is dimensionless because it is an argument of a trignometric function