1. Tardigrade
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  4. In the relation: ( dy / dt )=2 ω sin (ω t+φ0), the dimensional formula for (ω t+φ0) is:

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Q. In the relation : $\frac { dy }{ dt }=2 \omega \sin \left(\omega t+\phi_{0}\right),$ the dimensional formula for $\left(\omega t+\phi_{0}\right)$ is:

Physical World, Units and Measurements

Solution:

Here, $\left(\omega t+\phi_{0}\right)$ is dimensionless because it is an argument of a trignometric function