Q. In the reaction,
$K M n O_{4} + 16 H Cl \to 5 C l_{2} + 2 M n C l_{2} + 2 K Cl + 8 H_{2} O$
the reduction product is

1841 262 The d-and f-Block Elements Report Error

A

$C l_{2}$

B

$M n C l_{2}$

C

$H_{2} O$

D

$K Cl$

Solution:

Correct answer is (b) $M n C l_{2}$