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  4. In the reaction, KMnO4 + 16 HCl → 5Cl2 + 2MnCl2 + 2KCl + 8H2O the reduction product is

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Q. In the reaction,
$KMnO_4 + 16 HCl \to 5Cl_2 + 2MnCl_2 + 2KCl + 8H_2O$
the reduction product is

The d-and f-Block Elements

Solution:

Correct answer is (b) $MnCl_2$