Tardigrade
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Tardigrade
Question
Chemistry
In the reaction, I2 + 2S2O32- → 2I- + S4O2-6 Equivalent weight of iodine will be equal to
Q. In the reaction,
I
2
+
2
S
2
O
3
2
−
→
2
I
−
+
S
4
O
6
2
−
Equivalent weight of iodine will be equal to
2958
183
Redox Reactions
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A
its molecular weight
50%
B
1/2
of its molecular weight
50%
C
1/4
of its molecular weight
0%
D
twice of its molecular weight
0%
Solution:
1
2
0
+
2
e
−
2
I
−
n
=
2