Question

In the reaction,
$I_{2} + 2S_{2}O_{3}^{2-} \to 2I^{-} + S_{4}O^{2-}_{6}$
Equivalent weight of iodine will be equal to

• A. its molecular weight
• B. $1/2$ of its molecular weight
• C. $1/4$ of its molecular weight
• D. twice of its molecular weight

Answer 1

Answer: (B)

$1^{0}_{2} \xrightarrow{+2e^{-}} 2I^{-}$
$n=2$