Question

In the reaction, $HN{O}_3+H_{2}O\rightleftharpoons H_3{O}^{+}+N{O}_3^{-},$ the conjugate base of $HN{O}_3$ is

• A. $H_{2}O$
• B. $H_3{O}^{+}$
• C. $N{O}_3^{-}$
• D. $H_3{O}^{+}$ and $N{O}_3^{-}$

Answer 1

Answer: (C)

$\underset{\text{Acid}}{HN{O}_3}+\underset{\text{Base}}{H_{2}O}\rightleftharpoons \underset{\text{Conjugate acid}}{H_3{O}^{+}}+\underset{\text{Conjugate Base}}{N{O}_3^{-}}$