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Q. In the reaction, $HNO _{3}+ H _{2} O \rightleftharpoons H _{3} O ^{+}+ NO _{3}^{-},$ the conjugate base of $HNO _{3}$ is

Equilibrium

Solution:

$\underset{\text{Acid}}{{HNO_{3}}}+\underset{\text{Base}}{{H_{2}O}} \rightleftharpoons \underset{\text{Conjugate acid}}{{H_{3}O^{+}}}+\underset{\text{Conjugate Base}}{{NO^{-}_{3}}}$