In the reaction, 4A+2B+3C arrow A4B2C3 , what will be the number of moles of product formed, starting from 1 mole of A , 0.6 moles of B and 0.72 moles of C ?

Question

In the reaction, 4A+2B+3C arrow A4B2C3 , what will be the number of moles of product formed, starting from 1 mole of A , 0.6 moles of B and 0.72 moles of C ? (A) 0.25 (B) 0.3 (C) 0.24 (D) 2.32

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b06e1ddd232e662ee0c00d070cd91ca7-.png" /> In the present case, reactant 'C' will be the limiting reactant because it will give least amount of product on being completely consumed. As 3 mol C gives 1 mol product, So 0.72 mol C will give 0.24 mol of product.

Q. In the reaction, $4 A + 2 B + 3 C \to A_{4} B_{2} C_{3}$ , what will be the number of moles of product formed, starting from $1$ mole of $A$ , $0.6$ moles of $B$ and $0.72$ moles of $C$ ?

$0.25$

$0.3$

$0.24$

$2.32$

In the present case, reactant ' $C$ ' will be the limiting reactant because it will give least amount of product on being completely consumed.
As $3 m o l C$ gives $1 m o l$ product,
So $0.72 m o l C$ will give $0.24 m o l$ of product.

Q. In the reaction, 4A+2B+3C→A4​B2​C3​ , what will be the number of moles of product formed, starting from 1 mole of A , 0.6 moles of B and 0.72 moles of C ?

0.25

0.3

0.24

2.32