Question

In the reaction, $4A+2B+3C \rightarrow A_{4}B_{2}C_{3}$ , what will be the number of moles of product formed, starting from $1$ mole of $A$ , $0.6$ moles of $B$ and $0.72$ moles of $C$ ?

• A. $0.25$
• B. $0.3$
• C. $0.24$
• D. $2.32$

Answer 1

Answer: (C)

In the present case, reactant '$C$' will be the limiting reactant because it will give least amount of product on being completely consumed.
As $3 \,mol\, C$ gives $1 \,mol$ product,
So $0.72\, mol\, C$ will give $0.24 \,mol$ of product.