In the following figure the masses of the blocks A and B are same and each equal to m. The tensions in the strings O A and A B are T2 and T1, respectively. The system is in equilibrium with a constant horizontal force mg on B. the angle θ1 is

Question

In the following figure the masses of the blocks A and B are same and each equal to m. The tensions in the strings O A and A B are T2 and T1, respectively. The system is in equilibrium with a constant horizontal force mg on B. the angle θ1 is (A) 30° (B) 45° (C) 60° (D)  tan -1((1/2))

Tardigrade Admin · Accepted Answer

From the solution of previous problem, if we divide equation (ii) by equation (i), we get (T1 sin θ1/T1 cos θ1)=(m g/m g) ∴ tan θ1=1 or θ1=45°

Q. In the following figure the masses of the blocks $A$ and $B$ are same and each equal to $m$ . The tensions in the strings $O A$ and $A B$ are $T_{2}$ and $T_{1}$ , respectively. The system is in equilibrium with a constant horizontal force mg on $B$ . the angle $θ_{1}$ is

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$tan^{- 1} (\frac{1}{2})$

From the solution of previous problem, if we divide equation (ii) by equation (i), we get
$\frac{T _{1} s i n θ _{1}}{T _{1} c o s θ _{1}} = \frac{m g}{m g}$
$∴ tan θ_{1} = 1$
or $θ_{1} = 4 5^{\circ}$

Q. In the following figure the masses of the blocks A and B are same and each equal to m. The tensions in the strings OA and AB are T2​ and T1​, respectively. The system is in equilibrium with a constant horizontal force mg on B. the angle θ1​ is

30∘

45∘

60∘

tan−1(21​)