In the preparation of compounds of Xe , Bartlett had taken O2+PtF6- as a base compound. This is because

Question

In the preparation of compounds of Xe , Bartlett had taken O2+PtF6- as a base compound. This is because (A) both O2 and X e have same size. (B) both O2 and Xe have same electron gain enthalpy. (C) both O2 and Xe have almost same ionisation enthalpy. (D) both Xe and O2 are gases.

Tardigrade Admin · Accepted Answer

First compound of inert gases is prepared by Neill Barlett is XePtF6 O2+PtF6 arrow O2+[PtF6]- I.E.:O2≈ Xe Xe+PtF6 arrow Xe+PtF6-

Q. In the preparation of compounds of $X e$ , Bartlett had taken $O_{2}^{+} Pt F_{6}^{-}$ as a base compound. This is because

both $O_{2}$ and $X e$ have same size.

both $O_{2}$ and $X e$ have same electron gain enthalpy.

both $O_{2}$ and $X e$ have almost same ionisation enthalpy.

both $X e$ and $O_{2}$ are gases.

First compound of inert gases is prepared by Neill Barlett is $X e Pt F_{6}$
$O_{2} + Pt F_{6} \to O_{2}^{+} [Pt F_{6}]^{-}$
$I . E . : O_{2} \approx X e$
$X e + Pt F_{6} \to X e^{+} Pt F_{6}^{-}$

Q. In the preparation of compounds of Xe , Bartlett had taken O2+​PtF6−​ as a base compound. This is because

both O2​ and Xe have same size.

both O2​ and Xe have same electron gain enthalpy.

both O2​ and Xe have almost same ionisation enthalpy.

both Xe and O2​ are gases.