Question

In the preparation of compounds of $Xe$ , Bartlett had taken $O_{2}^{+}PtF_{6}^{-}$ as a base compound. This is because

• A. both $O_2$ and $X e$ have same size.
• B. both $O_{2}$ and $Xe$ have same electron gain enthalpy.
• C. both $O_{2}$ and $Xe$ have almost same ionisation enthalpy.
• D. both $Xe$ and $O_{2}$ are gases.

Answer 1

Answer: (C)

First compound of inert gases is prepared by Neill Barlett is $XePtF_{6}$
$O_{2}+PtF_{6} \rightarrow O_{2}^{+}\left[PtF_{6}\right]^{-}$
$I.E.:O_{2}\approx Xe$
$Xe+PtF_{6} \rightarrow Xe^{+}PtF_{6}^{-}$