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Tardigrade
Question
Physics
In the network shown in figure, power dissipated in 3 Ω is 12 W. Power dissipated in 4 Ω will be
Q. In the network shown in figure, power dissipated in
3
Ω
is
12
W
. Power dissipated in
4
Ω
will be
1758
198
Current Electricity
Report Error
A
4 W
51%
B
2 W
14%
C
64 W
27%
D
32 W
8%
Solution:
1
2
=
i
2
(
3
)
i
=
2
P
=
1
2
(
4
)
=
4
W