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Physics
In the network shown in figure, power dissipated in 3 Ω is 12 W. Power dissipated in 4 Ω will be
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Q. In the network shown in figure, power dissipated in $3\, \Omega$ is $12 \,W$. Power dissipated in $4 \,\Omega$ will be
Current Electricity
A
4 W
51%
B
2 W
14%
C
64 W
27%
D
32 W
8%
Solution:
$1_{2}=i^{2}(3)$
$i=2$
$P=1^{2}(4)=4\, W$