Question

In the ionic equation :
$Bi{O}_3^{-}+6H^{+}+X{e}^{-}⟶B{i}^{3+}+3H_{2}O$
the value of $X$ is -

• A. 3
• B. 4
• C. 2
• D. 6

Answer 1

Answer: (C)

$BiO{3}^{-}+6H^{+}+x{e}^{-}\to B{i}^{3+}+3H_{2}O$
By electron neutrality principle,
$-1+6+x(-1)=3+0$
$\Rightarrow +5+x(-1)=3$
$\Rightarrow x=+2$