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Q. In the ionic equation :
$BiO _{3}^{-}+6 H ^{+}+ Xe ^{-} \longrightarrow Bi ^{3+}+3 H _{2} O$
the value of $X$ is -

KCETKCET 2007Redox Reactions

Solution:

$BiO3^{-} + 6H^{+} + xe^{-} \rightarrow Bi^{3+} + 3H_2O$
By electron neutrality principle,
$-1 + 6 + x (-1) = 3 + 0$
$\Rightarrow +5 + x(-1) = 3$
$ \Rightarrow x = +2$