In the HCl molecule, the separation between the nuclei of the two atoms is about 1.27 overset texto mathop textA (1 overset texto mathop textA =10-10) . The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is:

Question

In the HCl molecule, the separation between the nuclei of the two atoms is about 1.27 overset texto mathop textA (1 overset texto mathop textA =10-10) . The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is: (A)  1 overset texto mathop textA  (B)  2.5 overset texto mathop textA  (C)  1.24 overset texto mathop textA  (D)  1.5 overset texto mathop textA

Tardigrade Admin · Accepted Answer

rcm=(mH× rH+mCl+rCl/mH+mCl) =(mH× 0+35.5 mH+rCl/mH+mCl) =1.24 AA (from chlorine atom)

Q. In the $H Cl$ molecule, the separation between the nuclei of the two atoms is about $1.27 A o$ $(1 A o = 10^{- 10})$ . The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is:

$1 A o$

$2.5 A o$

$1.24 A o$

$1.5 A o$

$0.9 A o$

$r_{c m} = \frac{m _{H} \times r _{H} + m _{Cl} + r _{Cl}}{m _{H} + m _{Cl}}$ $= \frac{m _{H} \times 0 + 35.5 m _{H} + r _{Cl}}{m _{H} + m _{Cl}}$ $= 1.24 \overset{˚}{A}$ (from chlorine atom)

Q. In the HCl molecule, the separation between the nuclei of the two atoms is about 1.27Ao (1Ao=10−10) . The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is:

1Ao

2.5Ao

1.24Ao

1.5Ao

0.9Ao

rcm​=mH​+mCl​mH​×rH​+mCl​+rCl​​ =mH​+mCl​mH​×0+35.5mH​+rCl​​ =1.24A˚ (from chlorine atom)