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Q. In the $ HCl $ molecule, the separation between the nuclei of the two atoms is about $ 1.27\overset{\text{o}}{\mathop{\text{A}}}\, $ $ (1\overset{\text{o}}{\mathop{\text{A}}}\,={{10}^{-10}}) $ . The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times as massive as hydrogen is:

KEAMKEAM 2002

Solution:

$ {{r}_{cm}}=\frac{{{m}_{H}}\times {{r}_{H}}+{{m}_{Cl}}+{{r}_{Cl}}}{{{m}_{H}}+{{m}_{Cl}}} $ $ =\frac{{{m}_{H}}\times 0+35.5\,{{m}_{H}}+{{r}_{Cl}}}{{{m}_{H}}+{{m}_{Cl}}} $ $ =1.24{\AA} $ (from chlorine atom)