Question

In the given $v-t$ graph, the distance travelled by the body in 5 second will be

• A. 20 m
• B. 40 m
• C. 80 m
• D. 100 m

Answer 1

Answer: (D)

Distance travelled in $5s=$ Area $OABC+$
Area $BCDE$ - Area $DNM$
$=\frac{1}{2}(OA+BC)\times OC+$
$\frac{1}{2}(BE+CD)\times BC+$
$\frac{1}{2}\times DN\times NM$
$=\frac{1}{2}(40+20)\times 2+\frac{1}{2}(1+2)\times 20+\frac{1}{2}(1)\cdot (20)$
$=60+30+10=100m$.