Thank you for reporting, we will resolve it shortly
Q.
In the given $v-t$ graph, the distance travelled by the body in 5 second will be
Motion in a Straight Line
Solution:
Distance travelled in $5 s =$ Area $O A B C+$
Area $B C D E$ - Area $D N M$
$= \frac{1}{2}(O A+B C) \times O C+$
$\frac{1}{2}(B E+C D) \times B C+$
$\frac{1}{2} \times D N \times N M$
$=\frac{1}{2}(40+20) \times 2+\frac{1}{2}(1+2) \times 20+\frac{1}{2}(1) \cdot(20)$
$=60+30+10=100\, m$.
