Question

In the given figure the steady state current $I$ is :

• A. zero
• B. 0.6 A
• C. 0.9 A
• D. 2 A

Answer 1

Answer: (D)

At steady state C becomes open
$\Rightarrow I=\frac{6}{R_{eq}}=\frac{6}{\frac{3}{2}+1.5}=2A$