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  4. In the given figure the steady state current I is :

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Q. In the given figure the steady state current $I$ is :Physics Question Image

Electrostatic Potential and Capacitance

Solution:

At steady state C becomes open
$\Rightarrow I =\frac{6}{ R _{e q}}=\frac{6}{\frac{3}{2}+1.5}=2 A$