In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6 Ω. Calculate the power dissipated in the whole circuit:

Question

In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6 Ω. Calculate the power dissipated in the whole circuit: (A) 1.32 W (B) 0.65 W (C) 2.2 W (D) 4.4 W

Tardigrade Admin · Accepted Answer

(1/ R texteq )=(1/4)+(1/8)+(1/12)+(1/6) =(6+3+2+4/24)=(15/24) R texteq =(24/15)=1.6 ⇒ R T =1.6+0.6=2.2 Ω P =( V 2/ R T )=((2.2)2/2.2)=2.2 W

Q. In the given figure, the emf of the cell is $2.2 V$ and if internal resistance is $0.6 Ω$ . Calculate the power dissipated in the whole circuit:

1.32 W

0.65 W

2.2 W

4.4 W

$\frac{1}{R _{eq}} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12} + \frac{1}{6}$
$= \frac{6 + 3 + 2 + 4}{24} = \frac{15}{24}$
$R_{eq} = \frac{24}{15} = 1.6$
$\Rightarrow R_{T} = 1.6 + 0.6 = 2.2Ω$
$P = \frac{V ^{2}}{R _{T}} = \frac{( 2.2 ) ^{2}}{2.2} = 2.2 W$

Q. In the given figure, the emf of the cell is 2.2V and if internal resistance is 0.6Ω. Calculate the power dissipated in the whole circuit: