In the given figure, if the dimensions of the two wires are same but materials are different, then Young’s modulus is

Question

In the given figure, if the dimensions of the two wires are same but materials are different, then Young’s modulus is (A) More for A than B (B) More for B than A (C) Equal for A and B (D) None of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/ffaf58b18df1cdd792cd578be974891b-.png" /> At same value of load A has less elongation than B.....(1) (F L/A Y)=Δ L ∵ L, A are same F - Load is also taken same So (1/Y) propto Δ L .....(2) Using conditions (1) and (2) We can say YA>YB Young's modulus of A greater than B

Q. In the given figure, if the dimensions of the two wires are same but materials are different, then Young’s modulus is

More for A than B

More for B than A

Equal for A and B

None of these

At same value of load
A has less elongation than $B$ .....(1)
$\frac{F L}{A Y} = Δ L$
$∵ L, A$ are same $F -$ Load is also taken same
So $\frac{1}{Y} \propto Δ L$ .....(2)
Using conditions (1) and (2)
We can say
$Y_{A} > Y_{B}$
${$ Young's modulus of $A$ greater than $B}$

Q. In the given figure, if the dimensions of the two wires are same but materials are different, then Young’s modulus is

More for A than B

More for B than A

Equal for A and B

None of these

At same value of load A has less elongation than B.....(1) AYFL​=ΔL ∵L,A are same F− Load is also taken same So Y1​∝ΔL .....(2) Using conditions (1) and (2) We can say YA​>YB​ { Young's modulus of A greater than B}

At same value of load
A has less elongation than $B$ .....(1)
$\frac{F L}{A Y} = Δ L$
$∵ L, A$ are same $F -$ Load is also taken same
So $\frac{1}{Y} \propto Δ L$ .....(2)
Using conditions (1) and (2)
We can say
$Y_{A} > Y_{B}$
${$ Young's modulus of $A$ greater than $B}$