Thank you for reporting, we will resolve it shortly
Q.
In the given figure, if the dimensions of the two wires are same but materials are different, then Young’s modulus is
Mechanical Properties of Solids
Solution:
At same value of load
A has less elongation than $B$.....(1)
$\frac{F L}{A Y}=\Delta L$
$\because L, A$ are same $F -$ Load is also taken same
So $\frac{1}{Y} \propto \Delta L$ .....(2)
Using conditions (1) and (2)
We can say
$Y_{A}>Y_{B}$
$\{$ Young's modulus of $A$ greater than $B \}$
