In the given figure, A B is an incident wavefront and E C is refracted wavefront. Speed of light in medium 1 is v1 and speed of light in medium 2 is v2. The ratio of ( sin i/ sin r) is equal to

Question

In the given figure, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/be333da4efa51f3dabf39cd69658733e-.png" /> A B is an incident wavefront and E C is refracted wavefront. Speed of light in medium 1 is v1 and speed of light in medium 2 is v2. The ratio of ( sin i/ sin r) is equal to (A) (B C/A C) (B) (A E/E C) (C) (B C/A E) (D) (A E/B C)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/734b0ea55aa46f89526003f02d1d8323-.png" /> sin i=(B C/A C)=(v1 τ/A C) and sin r=(A E/A C)=(v2 τ/A C) where, i and r are the angles of incidence and refraction, respectively. ( sin i/ sin r)=(B C / A C/A E / A C)=(B C/A E)

Q. In the given figure,

$A B$ is an incident wavefront and $EC$ is refracted wavefront. Speed of light in medium $1$ is $v_{1}$ and speed of light in medium $2$ is $v_{2}$ .
The ratio of $\frac{s i n i}{s i n r}$ is equal to

$\frac{BC}{A C}$

$\frac{A E}{EC}$

$\frac{BC}{A E}$

$\frac{A E}{BC}$

$sin i = \frac{BC}{A C} = \frac{v _{1} τ}{A C}$
and $sin r = \frac{A E}{A C} = \frac{v _{2} τ}{A C}$
where, $i$ and $r$ are the angles of incidence and refraction, respectively.
$\frac{s i n i}{s i n r} = \frac{BC / A C}{A E / A C} = \frac{BC}{A E}$

Q. In the given figure, AB is an incident wavefront and EC is refracted wavefront. Speed of light in medium 1 is v1​ and speed of light in medium 2 is v2​. The ratio of sinrsini​ is equal to

ACBC​

ECAE​

AEBC​

BCAE​