Question

In the given figure,

$A B$ is an incident wavefront and $E C$ is refracted wavefront. Speed of light in medium $1$ is $v_{1}$ and speed of light in medium $2$ is $v_{2}$.
The ratio of $\frac{\sin i}{\sin r}$ is equal to

• A. $\frac{B C}{A C}$
• B. $\frac{A E}{E C}$
• C. $\frac{B C}{A E}$
• D. $\frac{A E}{B C}$

Answer 1

Answer: (C)

$\sin i=\frac{B C}{A C}=\frac{v_{1} \tau}{A C}$
and $\sin r=\frac{A E}{A C}=\frac{v_{2} \tau}{A C}$
where, $i$ and $r$ are the angles of incidence and refraction, respectively.
$\frac{\sin i}{\sin r}=\frac{B C / A C}{A E / A C}=\frac{B C}{A E}$