In the given figure, 1 represents isobaric, 2 represents isothermal and 3 represents adiabatic processes of an ideal gas. If Δ U1, Δ U2, Δ U3 be the changes in internal energy in these processes respectively, then

Question

In the given figure, 1 represents isobaric, 2 represents isothermal and 3 represents adiabatic processes of an ideal gas. If Δ U1, Δ U2, Δ U3 be the changes in internal energy in these processes respectively, then (A) Δ U1<Δ U2<Δ U3 (B) Δ U1>Δ U3<Δ U2 (C) Δ U1=Δ U2>Δ U3 (D) Δ U1>Δ U2>Δ U3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f5ae5547f6ed6d88e655028303850a3d-.png" /> Δ T1=T0 Δ T2=0 Δ T3=-v e ⇒ Δ U1>Δ U2>Δ U3

Q.
In the given figure, $1$ represents isobaric, $2$ represents isothermal and $3$ represents adiabatic processes of an ideal gas. If $Δ U_{1}, Δ U_{2}, Δ U_{3}$ be the changes in internal energy in these processes respectively, then

$Δ U_{1} < Δ U_{2} < Δ U_{3}$

$Δ U_{1} > Δ U_{3} < Δ U_{2}$

$Δ U_{1} = Δ U_{2} > Δ U_{3}$

$Δ U_{1} > Δ U_{2} > Δ U_{3}$

$Δ T_{1} = T_{0}$
$Δ T_{2} = 0$
$Δ T_{3} = - v e$
$\Rightarrow Δ U_{1} > Δ U_{2} > Δ U_{3}$

Q. In the given figure, 1 represents isobaric, 2 represents isothermal and 3 represents adiabatic processes of an ideal gas. If ΔU1​,ΔU2​,ΔU3​ be the changes in internal energy in these processes respectively, then

ΔU1​<ΔU2​<ΔU3​

ΔU1​>ΔU3​<ΔU2​

ΔU1​=ΔU2​>ΔU3​

ΔU1​>ΔU2​>ΔU3​