Question

In the given diagram, the reading of the ammeter is
(when the internal resistance of the battery is zero) :

• A. 40/29 A
• B. 10/9 A
• C. 5/3 A
• D. 2 A

Answer 1

Answer: (D)

Potential is same for resistors connected in parallel.
In the given circuit diagram, $4\Omega$ and $5\Omega$ resistors are connected in parallel, hence potential drop across each is $10V$.
From Ohms law $V=IR$
where $I$ is current and $R$ is resistance.
$\therefore I=\frac{V}{R}=\frac{10}{5}=2A$