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Tardigrade
Question
Physics
In the given circuit the peak voltage across C, L and R are 30 V, 110 V and 60 V respectively. The rms value of the applied voltage is
Q. In the given circuit the peak voltage across
C
,
L
and
R
are
30
V
,
110
V
and
60
V
respectively. The rms value of the applied voltage is
7500
184
KCET
KCET 2020
Electromagnetic Induction
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A
100 V
21%
B
200 V
28%
C
70.7 V
40%
D
141 V
12%
Solution:
V
0
=
V
R
2
+
(
V
L
−
V
C
)
2
=
6
0
2
+
(
11
0
2
−
3
0
2
)
=
100
V
r
m
s
=
2
V
0
=
2
100
=
2
100
×
2
2
=
100
×
2
2
=
50
×
1.414
=
70.7
V