In the given circuit the peak voltage across C, L and R are 30 V, 110 V and 60 V respectively. The rms value of the applied voltage is

Question

In the given circuit the peak voltage across C, L and R are 30 V, 110 V and 60 V respectively. The rms value of the applied voltage is (A) 100 V (B) 200 V (C) 70.7 V (D) 141 V

Tardigrade Admin · Accepted Answer

V0=√VR2+(VL-VC)2 =√602+(1102-302)=100 Vr m s=(V0/√2)=(100/√2) =(100/√2) × (√2/√2)=100 × (√2/2) =50 × 1.414=70.7 V

Q. In the given circuit the peak voltage across $C, L$ and $R$ are $30 V$ , $110 V$ and $60 V$ respectively. The rms value of the applied voltage is

100 V

200 V

70.7 V

141 V

$V_{0} = V_{R}^{2} + (V_{L} - V_{C})^{2}$
$= 6 0^{2} + (11 0^{2} - 3 0^{2}) = 100$
$V_{r m s} = \frac{V _{0}}{2} = \frac{100}{2}$
$= \frac{100}{2} \times \frac{2}{2} = 100 \times \frac{2}{2}$
$= 50 \times 1.414 = 70.7 V$

Q. In the given circuit the peak voltage across C,L and R are 30V, 110V and 60V respectively. The rms value of the applied voltage is