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Physics
In the given circuit the peak voltage across C, L and R are 30 V, 110 V and 60 V respectively. The rms value of the applied voltage is
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Q. In the given circuit the peak voltage across $C, L$ and $R$ are $30 \,V$, $110 \,V$ and $60\, V$ respectively. The rms value of the applied voltage is
KCET
KCET 2020
Electromagnetic Induction
A
100 V
15%
B
200 V
35%
C
70.7 V
37%
D
141 V
14%
Solution:
$V_{0}=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}}$
$=\sqrt{60^{2}+\left(110^{2}-30^{2}\right)}=100$
$V_{r m s}=\frac{V_{0}}{\sqrt{2}}=\frac{100}{\sqrt{2}}$
$=\frac{100}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}=100 \times \frac{\sqrt{2}}{2}$
$=50 \times 1.414=70.7 \,V$