In the given circuit, the current through the resistor of 2 kΩ is:

Question

In the given circuit, the current through the resistor of 2 kΩ is: (A) 2 mA (B) 4 mA (C) 6 mA (D) 1 mA

Tardigrade Admin · Accepted Answer

The voltage across 2 k Ω resistor =12 V (since applied voltage is more than breakdown voltage for Zener diode) Therefore, current passing through 2 k Ω resistor =(12/2 × 103)=6 × 10-3 A =6 mA

Q. In the given circuit, the current through the resistor of 2 $k Ω$ is:

2 mA

4 mA

6 mA

1 mA

The voltage across $2 k Ω$ resistor $= 12 V$ (since applied voltage is more than breakdown voltage for Zener diode)
Therefore, current passing through $2 k Ω$ resistor
$= \frac{12}{2 \times 1 0 ^{3}} = 6 \times 1 0^{- 3} A = 6 m A$

Q. In the given circuit, the current through the resistor of 2 kΩ is: