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Q.
In the given circuit, the current through the resistor of 2 $k\Omega$ is:
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
The voltage across $2 k \Omega$ resistor $=12 V$ (since applied voltage is more than breakdown voltage for Zener diode)
Therefore, current passing through $2 k \Omega$ resistor
$=\frac{12}{2 \times 10^{3}}=6 \times 10^{-3} A =6 mA$
