Question

In the given circuit, the charge on 4 $\mu$F capacitor will be :

• A. 5.4 $\mu$C
• B. 24 $\mu$C
• C. 13.4 $\mu$C
• D. 9.6 $\mu$C

Answer 1

Answer: (B)

So total charge flow = $q=5.4\mu F\times 10V$
$=54\mu C$
The charge will be distributed in the ratio of
capacitance
$\Rightarrow \frac{q_1}{q_2}=\frac{2.4}{3}=\frac{4}{5}$
$\therefore 9X=54\mu C\Rightarrow X=6\mu C$
$\therefore$ charge on $4\mu F$ capacitor
will be = $4X=4\times 6\mu C$
$=24\mu C$