Q.
In the given circuit, the charge on 4 $\mu$F capacitor will be :
Solution:
So total charge flow = $q = 5.4 \mu F \times 10V$
$ \, \, \, \, \, \, \, \, \, \, \, \, =54 \mu C$
The charge will be distributed in the ratio of
capacitance
$\Rightarrow \, \, \, \frac{q_1}{q_2} = \frac{2.4}{3} = \frac{4}{5}$
$\therefore \, \, 9X = 54 \mu C \Rightarrow \, \, \, X = 6 \mu C$
$\therefore $ charge on $4 \mu F$ capacitor
will be = $4X = 4 \times 6 \mu C$
$ \, \, \, \, \, \, \, \, \, = 24 \mu C$
