Question

In the given circuit, if $V_{BE}=0.7V$ and $\beta =100$, then find $V_{CE}$ (in volt).

Answer 1

Answer: 6.28

$I_B=\frac{10-V_{BE}}{1M\Omega }=9.3\mu A$
$I_C=\beta I_B=9.3\times 100\mu A=0.93mA$
and $V_{CE}=10-I_C{R}_C$
$V_{CE}=10-0.93\times 4=6.28V$