Question

In the given circuit current through the zener diode is :-

• A. 30 mA
• B. 24 mA
• C. 36 mA
• D. 6 mA

Answer 1

Answer: (B)

$I_{\text{Load }}=\frac{6}{1\times 10^3}=6mA$
$I_{100\Omega }=\frac{9-6}{100}=30mA$
$I_Z=I_{100}-I_L=30-6=24mA$