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Q. In the given circuit current through the zener diode is :-Physics Question Image

Solution:

$I _{\text {Load }}=\frac{6}{1 \times 10^{3}}=6\, mA$
$I _{100\, \Omega}=\frac{9-6}{100}=30\, mA$
$I _{ Z }= I _{100}- I _{ L }=30-6=24\, mA$