Question

In the given circuit, current through $3\Omega$ resistor is

• A. 1.5 A
• B. 2.0 A
• C. 1.0 A
• D. 0.5 A

Answer 1

Answer: (C)

Net resistance of the circuit,
$R=2+\frac{6\times 3}{6+3}=4\Omega$
$I=\frac{V}{R}=\frac{6}{4}=1.5A$
Current through $3\Omega =\frac{(6\Omega )(1.5A)}{(3\Omega +6\Omega )}=1A$