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Q. In the given circuit, current through $3 \, \Omega $ resistor isPhysics Question Image

COMEDKCOMEDK 2007Current Electricity

Solution:

Net resistance of the circuit,
$R = 2 + \frac{6 \times 3}{6 +3} = 4 \Omega $
$I = \frac{V}{R} = \frac{6}{4} = 1.5 \, A $
Current through $3 \Omega = \frac{(6 \Omega)(1.5 A)}{(3 \Omega + 6 \Omega)} = 1 A$

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