The normal reaction 'N' for a vehicle of 800 kg mass, negotiating a turn on a 30° banked road at maximum possible speed without skidding is

Question

The normal reaction 'N' for a vehicle of 800 kg mass, negotiating a turn on a 30° banked road at maximum possible speed without skidding is (A) 10.2 (B) 7.2 (C) 12.4 (D) 6.96

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5fa05195e57b8cbcbbfa161d6e85ce9b-.png" /> At v max f will be limiting in nature. ∴ Balancing force in vertical direction, N cos 30°-m g-μ N cos 60°=0 ⇒ N[ cos 30°-μ cos 60°]=m g ∴ N=(800 × 10/(0.87-0.1)) ≈ 10.2 × 103 kgm / s 2

Q. The normal reaction ' $N$ ' for a vehicle of $800 k g$ mass, negotiating a turn on a $3 0^{\circ}$ banked road at maximum possible speed without skidding is

10.2

7.2

12.4

6.96

At $v_{m a x} f$ will be limiting in nature.
$∴$ Balancing force in vertical direction,
$N cos 3 0^{\circ} - m g - μ N cos 6 0^{\circ} = 0$
$\Rightarrow N [cos 3 0^{\circ} - μ cos 6 0^{\circ}] = m g$
$∴ N = \frac{800 \times 10}{( 0.87 - 0.1 )} \approx 10.2 \times 1 0^{3} k g m / s^{2}$

Q. The normal reaction 'N' for a vehicle of 800kg mass, negotiating a turn on a 30∘ banked road at maximum possible speed without skidding is

10.2

7.2

12.4

6.96

At vmax​f will be limiting in nature. ∴ Balancing force in vertical direction, Ncos30∘−mg−μNcos60∘=0 ⇒N[cos30∘−μcos60∘]=mg ∴N=(0.87−0.1)800×10​≈10.2×103kgm/s2

Q. The normal reaction ' $N$ ' for a vehicle of $800 k g$ mass, negotiating a turn on a $3 0^{\circ}$ banked road at maximum possible speed without skidding is

At $v_{m a x} f$ will be limiting in nature.
$∴$ Balancing force in vertical direction,
$N cos 3 0^{\circ} - m g - μ N cos 6 0^{\circ} = 0$
$\Rightarrow N [cos 3 0^{\circ} - μ cos 6 0^{\circ}] = m g$
$∴ N = \frac{800 \times 10}{( 0.87 - 0.1 )} \approx 10.2 \times 1 0^{3} k g m / s^{2}$