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Q. The normal reaction '$N$' for a vehicle of $800\, kg$ mass, negotiating a turn on a $30^{\circ}$ banked road at maximum possible speed without skidding is

JEE MainJEE Main 2021Laws of Motion

Solution:

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At $v_{\max } f$ will be limiting in nature.
$\therefore $ Balancing force in vertical direction,
$N \cos 30^{\circ}-m g-\mu N \cos 60^{\circ}=0$
$\Rightarrow N\left[\cos 30^{\circ}-\mu \cos 60^{\circ}\right]=m g$
$\therefore N=\frac{800 \times 10}{(0.87-0.1)} \approx 10.2 \times 10^{3} kgm / s ^{2}$