In the following sequence of reactions, the alkene affords the compound B . CH3-CH=CH - CH3 oversetO3 arrow A oversetZn / H2 O arrow B is:

Question

In the following sequence of reactions, the alkene affords the compound B . CH3-CH=CH - CH3 oversetO3 arrow A oversetZn / H2 O arrow B is: (A) CH3COCH3 (B) CH3CH2COCH3 (C) CH3CHO (D) CH3CH2CHO

Tardigrade Admin · Accepted Answer

Ozonolysis reaction takes place in which ozone gives its oxygens to but-

2

-ene (unsaturated compound) to form carbonyl compound. Here reductive ozonolysis reaction takes place in presence of zinc which forms aldehyde and ketone on breaking of double bond. As shown below:

C H_{3} - C H = C H - C H_{3} \to_{Z n / H_{2} O}^{O_{3}} 2 C H_{3} - C H O

Q. In the following sequence of reactions, the alkene affords the compound $B$ . $C H_{3} - C H = C H - C H_{3} \to O_{3} A \to Z n / H_{2} O B$ is:

$C H_{3} COC H_{3}$

$C H_{3} C H_{2} COC H_{3}$

$C H_{3} C H O$

$C H_{3} C H_{2} C H O$

Q. In the following sequence of reactions, the alkene affords the compound B . CH3​−CH=CH−CH3​→O3​A→Zn/H2​OB is:

CH3​COCH3​

CH3​CH2​COCH3​

CH3​CHO

CH3​CH2​CHO

Q. In the following sequence of reactions, the alkene affords the compound $B$ . $C H_{3} - C H = C H - C H_{3} \to O_{3} A \to Z n / H_{2} O B$ is:

$C H_{3} COC H_{3}$

$C H_{3} C H_{2} COC H_{3}$

$C H_{3} C H O$

$C H_{3} C H_{2} C H O$