Question

In the following sequence of reactions, the alkene affords the compound $B$ . $CH_{3}-CH=CH - CH_{3}\overset{O_{3}}{ \rightarrow }A\overset{Zn / H_{2} O}{ \rightarrow }B$ is:

• A. $CH_{3}COCH_{3}$
• B. $CH_{3}CH_{2}COCH_{3}$
• C. $CH_{3}CHO$
• D. $CH_{3}CH_{2}CHO$

Answer 1

Answer: (C)

Ozonolysis reaction takes place in which ozone gives its oxygens to but- $2$ -ene (unsaturated compound) to form carbonyl compound. Here reductive ozonolysis reaction takes place in presence of zinc which forms aldehyde and ketone on breaking of double bond. As shown below:
$CH_{3}-CH=CH-CH_{3} \rightarrow _{Zn / H_{2} O}^{O_{3}}2CH_{3}-CHO$